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Comments and Results for 'Jigsaw Killer-6 200'

StateTypeTitleSizePlayedAvg timeRating (#users)YoursYour bestPublishedExpires
UnplayedJigsaw KillerJigsaw Killer-6 2006x6916:18Easy (63)Subscribers only13th Jul-
Show full chart rankings for Jigsaw Killer-6 200
Your puzzle statistics First solution time distribution Overall puzzle statistics
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Slowest 10% not shown
0:00
10:04

Solution time without 'show wrong'
Slowest 10% not shown
0:00
10:04

Unaided first solution time
Slowest 10% not shown
0:00
8:25
Completed by78 users
Best time without any aid2:01 by lisamcqueen
Best time with major aid1:58 by purrs
Best time with show wrong
or multiple sessions
1:34 by fsolera
Average solve time with no or minor aid6:04
Average difficulty rating - all players1.5/10.0
Average difficulty rating - no aid1.3/10.0
Average difficulty rating - major aid1.7/10.0
Average difficulty rating - show wrong or
multiple sessions
2.2/10.0
5 comments (Add new comment)
Posted 13th Jul 2019 at 15:44
Elisabeth Daily subscriber Rated puzzle: Moderate Completion time: 12:40 Used 'check puzzle' when incorrect
Are you able to solve this without using the 5 cell with 16? I was stuck until I eventually spotted this!!:)
Posted 13th Jul 2019 at 16:21
Penelope Daily subscriber Rated puzzle: Moderate Completion time: 8:25
Me too, Elisabeth
Posted 13th Jul 2019 at 23:23
JoergWausW Daily subscriber Completion time: 2:25
Elisabeth,
yes, it is possible not to use any 16, but it took me a while to figure it out.
1)
-> the 9-boxes in the corners can not have 1 or 2.
-> in the left and right column 1 and 2 must be green/pink, so you can erase 1 and 2 in the second columns (maybe not needed)
2)
Now look at the bottom row and/or the top row (I prefer the bottom row - do the same symmetrically in the top row).
The three squares next to 11 have to sum up to 10. That only leaves 3 or 4 for the corner squares in the 9 boxes, because otherwise 12 can't be reached
3)
Neither the 11- nor the 12-box (with gray squares in bottom row) can have both 1 and 2.
That's why the 2x2 square or the 5x5 square can not have 1 or 2 because the 12 would eat up too many high numbers (6 and (4 or 5)) and you can't add up to 11 using the 1.
These 2x2 and 5x5 squares can not be 3 or 4, because they have the same color as the corner sqares and it wouldn't sum up to 10 again.
4) with 5/6 taken in blue (and symmetrical) orange areas you can now can proceed.

If you still get stuck, it might help to eliminate high numbers in the 10 box in the pink area (now you might need the deleted 1/2 in the pink area, second column from the right).

Posted 14th Jul 2019 at 15:47
Elisabeth Daily subscriber Rated puzzle: Moderate Completion time: 12:40 Used 'check puzzle' when incorrect
Thanks, JoergWausW, I thought you might respond! We had a conversation about another 6x6 puzzle some little time ago.
Earlier I had obtained the 34 in the corners and the two sets of 56 and your suggestions set me off acually on a different path which I discovered eliminated the 5 from each 16 automatically. Getting rid of 5 in both 16s is probably the quickest way of solving though.
Happy solving:)
Posted 14th Jul 2019 at 17:08
JoergWausW Daily subscriber Completion time: 2:25
Getting rid of 5 in both 16s is probably the quickest way of solving though. <-- agreed. I used it, too.
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Key

  • A yellow/light blue highlight in the time distribution charts highlights your time, where relevant.
  • Rating scores out of 10.0 show the average difficulty rating chosen by users, where 1.0 is "Easy" and 10.0 is "Hard".
  • If a puzzle is opened more than once, including by loading from a saved position, then this is potentially a significant aid so it is listed as being completed with 'multiple sessions' for the purpose of the best time/average rating displays above.
  • Minor aid is defined as no more than one use of 'Check solution' when incomplete and/or no more than one use of 'Check solution' when wrong; and/or using highlighting aids (show repeated digits, show broken inequalities and show valid/invalid placements [slitherlink] only). Major aid is any and all other use of the solving aids except for 'show wrong'.

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